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3 years ago

How do populations survive when the environment changes?

Chemistry

2 answers:

kkurt [141]3 years ago

6 0

With adaptation, or a mutation that provides a better way for the organism to survive in the new environment

katrin [286]3 years ago

3 0

Answer:

adaptation?

Explanation:

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What is the [oh−] of a solution with ph 5.75

Gekata [30.6K]

[ H₃O⁺] = 10 ^- pH

[ H₃O⁺] = 10 ^ (- 5.75 )

[H₃O⁺] = 1.778x10⁻⁶ M

Kw = [ H₃O⁺] x [ OH⁻]

1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]

[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶

[OH⁻] = 5.62x10⁻⁹ M

hope this helps!

5 0

3 years ago

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You get a can of soda from the vending machine and your “friend” maliciously shakes it when you’re not looking. You open the can

vaieri [72.5K]

Physical Change because a new substance was not created and if it was a chemical change, a new substance would have to be created.

8 0

4 years ago

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At 517 mm Hg and 24 °C, a sample of gas occuples a volume of 95 ml. The gas is transferred to a 225-ml flask and the temperature

vodomira [7]

Answer:

$P_2=194.78mmHg$

Explanation:

Hello,

In this case, we employ the combined ideal gas law in order to understand the volume-gas-pressure behavior as shown below:

$\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}$

Hence, solving for the final pressure P2, we obtain (do not forget temperature must be absolute):

$P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{517mmHg*95mL*(-8.0+273.15)K}{(24+273.15)K*225mL}\\ \\P_2=194.78mmHg$

Best regards.

7 0

4 years ago

Read 2 more answers

Whitney's tidal volume, which is the volume of air that she inhales and exhales, was 0.56 L . Her tidal volume was measured at a

ipn [44]

Given:

Volume of air inhaled V = 0.56 L

Temperature T = 37 C = 37 +273 = 310 K

Pressure P = 744 mmHg = 744/760 = 0.979 atm

% N2 in air = 78%

To determine:

The moles of N2 inhaled in one breath

Explanation:

Step 1: Calculate the moles of air inhales

Based on the ideal gas law:

PV = nRT

where P = pressure, T = temperature, V = volume, n = # moles

R = gas constant = 0.0821 L atm/mol-K

n = PV/RT = 0.979 * 0.56/0.0821*310 = 0.0215 moles of air

Step 2: Calculate the moles of N2

It is given that air contains 78% N2

Therefore:

moles of N2 = 0.0215 * 78/100 = 0.0168 moles

Ans: moles of N2 = 0.0168

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4 years ago

NEED HELP NOW

sertanlavr [38]

Answer:

you need to use the of the five to the report to the report that there are two different and the other two are the same limited as the or the two of the 8

Explanation:

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3 years ago