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2 years ago

How many atoms of San are in 0.796 moles of this element

Chemistry

1 answer:

xenn [34]2 years ago

8 0

Answer:

4.8× 10²³ atoms

Explanation:

Given data:

Number of moles of San element = 0.796 mol

Number of atoms present = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.796 mol × 6.022 × 10²³ atoms / 1mol

4.8× 10²³ atoms

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How many grams of sodium sulfate will be formed if you start with 200.0

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2 years ago

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Answer:

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2 years ago

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1 year ago

1. Find the masses of the following amounts.

In-s [12.5K]

The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

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2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

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1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

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3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

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Learn more about mole here ;

brainly.com/question/21323029

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1 year ago