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Simora [160]
3 years ago
8

How many atoms of San are in 0.796 moles of this element

Chemistry
1 answer:
xenn [34]3 years ago
8 0

Answer:

4.8× 10²³ atoms

Explanation:

Given data:

Number of moles of San element = 0.796 mol

Number of atoms present = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.796 mol ×  6.022 × 10²³ atoms / 1mol

4.8× 10²³ atoms

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Solid aluminum (Al) and chlorine (C1,) gas react to form solid aluminum chloride (A1CI2). Suppose you have 7.0 mol of Al and 1.0
WITCHER [35]

Answer:

6.3 moles

Explanation:

From the balanced equation of reaction:

2Al + 3Cl_2 --> 2AlCl_3

2 moles of aluminium reacts with 3 moles of chlorine gas to form 2 moles of AlCl3.

Therefore, 1 mole of chlorine will require: 2 x 1/3 = 0.67 mole of aluminium.

Hence, 0.67 mole of aluminium will be needed for 1 mole of chlorine. If 7 moles of aluminium is present, then:

   7 - 0.67 = 6.33 moles of aluminium will be left.

To the nearest 0.1, it means 6.3 moles of aluminium will be left.

4 0
3 years ago
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I (s) ⇌ NH3 (g) + HI (g) At 400 ºC, Kp = 0.215. Calcul
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<u>Answer:</u> The partial pressure of ammonia is 0.464 atm

<u>Explanation:</u>

For the given chemical equation:

                  NH_4I(s)\rightleftharpoons NH_3(g)+HI(g)

Initial:               1

At eqllm:        1-x                 x         x

The expression for K_p for the following equation is:

K_p=p_{NH_3}\times p_{HI}

The partial pressures of solids and liquids are taken as 1 in the equilibrium expression.

We are given:

K_p=0.215

Putting values in above equation, we get:

0.215=x\times x\\\\x=0.464atm

Hence, the partial pressure of ammonia is 0.464 atm

5 0
3 years ago
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