How many atoms of San are in 0.796 moles of this element
1 answer:
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The volume of concentrated HCl : 2.073 ml
<h3>Further explanation</h3>Given
37% HCl by mass; density 1.19 g/mL
Required
The volume of concentrated HCl
Solution
Conversion to molarity :
37% x 1.19 g/ml =0.4403 g/ml
g/ml to mol/L :
=0.4403 g/ml x 1000 ml/L : 36.5 g/mol
=12.06 mol/L
or we can use formula :
Dilution formula :
M₁V₁=M₂V₂
12.06 M x V₁ = 0.1 M x 0.25 L
V₁ = 0.0021 L = 2.073 ml
Answer:
a) No. of moles of hydrogen needed = 5.4 mol
b) Grams of ammonia produced = 27.2 g
Explanation:
a)
No. of moles of nitrogen = 1.80 mol
1 mole of nitrogen reacts with 3 moles of hydrogen
1.80 moles of nitrogen will react with
= 1.80 × 3 = 5.4 moles of hydrogen
b)
No. of moles of hydrogen = 2.4 mol
It is given that nitrogen is present in sufficient amount.
3 moles of hydrogen produce 2 moles of
2.4 moles of hydrogen will produce
=
Molar mass of ammonia = 17 g/mol
Mass in gram = No. of moles × Molar mass
Mass of ammonia in g = 1.6 × 17
= 27.2 g