Question

A 3.0-kilogram object is placed on a frictionless track at point A and released from rest.

Answer 1

Answer:

Explanation:

From the given information:

The gravitational potential energy at A is:

$PE_A = mgh$

GIven that:

mass(m) = 3

height (h) = 3

$PE_A =3\times 9.81 \times 3$

$\mathbf {PE_A =88.29 \ J }$

b)

Using the conservation of mechanical  energy:

$PE_A+KE_A = PE_B + KE_B$

$88.29 +0 = 3(9.8)(1) + KE_B$

$88.29 = 29.4 + KE_B$

$KE_B = 88.29 -29.4$

$\mathbf{ KE_B= 58.89 \ J}$