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3 years ago

Explain Newtons Laws

1 answer:

8 0

1) Newton first law of motion: state“If a body is at rest it reamain at rest and if it is in a motion it continu its motion unless a net external force acting on it”

This law also called law of inertia

2) Newton second law of motion: states that ‟acceleration to the force acting on the body and inversky proportional to the mass of the body”

3) Newton's third law of motion: It is not possible to exert a force abody with out the body exerting a forces in the opposite direction.

These forces are called action and reaction forces

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THANK YOU.

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A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the veloc

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Answer:

2.22m/s to the left

Explanation:

Given parameters:

Initial position = +125m

Final position = -75m

Motion time = 90s

Unknown:

Velocity of the steel ball = ?

Solution:

The velocity of the steel ball is given as the displacement divided by the time;

Velocity = $\frac{displacement}{time}$

The net displacement of the ball = 125- (-75) = 200m to the left

Input the parameters and solve for the velocity;

Velocity = $\frac{200}{90}$ = 2.22m/s to the left

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3 years ago

A disc of mass m slides with negligible friction along a flat surface with a velocity v. The disc strikes a wall head-on and bou

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Answer:

-v/2

Explanation:

Given that:

a disc of mass m

Collides with the wall going through a sliding motion on on the plane smooth surface.

Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.

We know, kinetic energy is given as:

$KE_i=\frac{1}{2}. m.v^2$

consider this to be the initial kinetic energy of the body.

Now after collision:

$KE_f=\frac{1}{4}\times KE_i$

$KE_f=\frac{1}{4} \times \frac{1}{2}\times m.v^2$

Considering that the mass of the body remains constant before and after collision.

$KE_f=\frac{1}{2}\times m.(\frac{v}{2})^2$

Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.

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3 years ago

A rod is pivoted about its center and oriented horizontally. A 5.0-N force directed upward is applied 4.0 m to the left of the p

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Answer:

The total torque is 27.5 Nm

Explanation:

Given;

5.0-N force directed upward is applied 4.0 m to the left of the pivot,

5.0-N force directed upward is applied 1.5 m to the right of the pivot,

Taking the moment about the pivot, the total torque is given by;

τ = Fr

where;

F is the appllied force

r is the radius of the force arm

τ = (5 N x 4 m) + (5 N x 1.5 m)

τ = 27.5 Nm

Therefore, the total torque is 27.5 Nm

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3 years ago

Explain Newtons Laws​

Explain Newtons Laws