Answer:
coefficient of friction =0.268
magnitude of force P=289.78N
Explanation:
The coefficient of friction is obtained by mgsinФ/mgcosФ=tanФ=tan15=0.268
force P is horizontal as stated in the question, horizontal component of P=mgcosФ=30*10*cos15=289.78
As given in the problem statement
frequency=1 KHz=1*10^3 Hz
V(t) is represented as
v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)
v ( t ) = 5 s i n ( 2 π 1000 t ) + 0.05 s i n ( 2 π 3000 t )
Total harmonic distortion will be 234 Pi
1 and 3
6.86g/mL
Train Bike Truck
