Answer:
the stove energy went into heating water is 837.2 kJ.
Explanation:
given,
mass of water = 2000 grams
initial temperature = 0° C
Final temperature = 100° C
specific heat of water (c) = 4.186 joule/gram
energy = m c Δ T
= 2000 × 4.186 × (100° - 0°)
= 837200 J
= 837.2 kJ
hence, the stove energy went into heating water is 837.2 kJ.
The electric field between plates is 4000V/m.
An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles.
The value of the electric field has dimensions of force per unit charge. In the metre-kilogram-second and SI systems, the appropriate units are newtons per coulomb, equivalent to volts per metre.
The voltage between points A and B is
V=E.d
E =V/d (uniform E- field only)
where d is the distance from A to B, or the distance between the plates.
Given:
distance d = 3 cm
voltage V = 120 V
Electric field E = V/d
E = 120 V / 3cm
E = 40 V / 1 cm [ 1 cm = 1/100 m ]
E = 4000 V/m.
Learn more about Electric field here:
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Answer:
When the temperature decreases the particals start to slow down.
Answer: 3 A
Explanation:
According to<u> Ohm's law</u>:
Where:
is the voltage
is the resistance of the resistor
is the electric current (the value we want to find)
Isolating :
Finally:
