Use the conservation of angular momentum; angular momentum at the beginning = angular momentum at the end
Conservation of angular momentum:
I1 w1 = I2 w2
Where I is the moment of inertia. For a sphere, I=2/5 m R^2. Substituting into the equation above we get
w2 = I1 w1 / I2 = w1 m1 R1^2 / (m2 R2^2)
w2 = w1 4 * (R1/R2)^2
= 4*(1)*(7E5/7.5)^2
= 3.48E10 revs/(17days)
= 2.04705882 x 10^9 revs/sec
Answer:
1 = 5.4 J
2 = 0.1979 C
3 = 5
Explanation:
Energy in a capacitor, E is
E = 1/2 * C * V²
E = 1/2 * 3000*10^-6 * 60²
E = 1/2 * 3000*10^-6 * 3600
E = 1/2 * 10.8
E = 5.4 J
E = Q²/2C = 6.53 J
E * 2C = Q²
Q² = 6.53 * 2 * 3000*10^-6
Q² = 13.06 * 3000*10^-6
Q² = 0.03918
Q = √0.03918
Q = 0.1979 C
The Capacitor, C is inversely proportional to the distance of separation, D. Thus, if D is increased by 5 to be 5D, then C would be C/5. And therefore, our energy stored in the capacitor is increased by a factor of 5.
Answer:
8.45m/s = recoil speed
Explanation:
Momentum = mass • velocity
9.8kg • 88.03m/s = 102.1kg • recoil speed
862.694kg•m/s = 102.1kg • recoil speed
divide both sides by 102.1kg
8.45m/s = recoil speed
Answer:
120V
Explanation:
Given parameters:
Current = 6A
Resistance = 20Ω
Unknown:
Voltage = ?
Solution:
According to ohms law;
V = IR
Where V is the voltage
I is the current
R is the resistance
Now, insert the parameters and solve;
V = 6 x 20 = 120V
