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2 years ago

Show that:sin60=2tan60/1+tan²60

Mathematics

1 answer:

Ulleksa [173]2 years ago

6 0

Answer:

Step-by-step explanation:

2 tan(60) = 2 * (sqrt(3)/2 = sqrt(3)

1 + tan^2(60) = 1/cos^2(60) = 1//1/4 = 4

The answer is going to look a little convoluted but it should be correct.

The answer so far is sqrt(3) /4

sin(60) = sqrt(3)/2

of the 4, two is needed to get sqrt(3)/2

So far then we have sin(60)/2

If we multiply by 2 as in (sin(60)/2) we get just sin(60)

2* sqrt(3) /4 then = 2 sin(60)

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Step-by-step explanation:

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3 years ago

Solve the problem for Y 3x + y = 7

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3 years ago

A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence

belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

$\mathbf{n = 5}$ --- the number of digits

$\mathbf{r = 3}$ ---- the number of actions

Each of the three actions can either be:

Pressing one button
Pressing a pair of buttons

The number of ways of pressing a button is:

$\mathbf{n_1 = ^5C_1}$

Apply combination formula

$\mathbf{n_1 = \frac{5!}{(5-1)!1!}}$

$\mathbf{n_1 = \frac{5!}{4!1!}}$

$\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}$

$\mathbf{n_1 = 5}$

The number of ways of pressing a pair is:

$\mathbf{n_2 = ^5C_2}$

Apply combination formula

$\mathbf{n_2 = \frac{5!}{(5-2)!2!}}$

$\mathbf{n_2 = \frac{5!}{3!2!}}$

$\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}$

$\mathbf{n_2 = 10}$

So, the number of ways of performing one action is:

$\mathbf{n =n_1 + n_2}$

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For the three actions, the number of ways is:

$\mathbf{Action = n^3}$

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$\mathbf{Action = 3375}$

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

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2 years ago

Write three fractions equivalent to -4/4

Aleonysh [2.5K]

-2/2, -3/3, -1/1

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2 years ago

Read 2 more answers

How do you find the end behavior?

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

In this lesson, you will learn what the "end behavior" of a polynomial is and how to analyze it from a graph or from a polynomial equation.

What's "end behavior"?

The end behavior of a function

ff describes the behavior of the graph of the function at the "ends" of the

xx-axis.

In other words, the end behavior of a function describes the trend of the graph if we look to the right end of the

xx-axis (as

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+∞plus, infinity) and to the left end of the

xx-axis (as

xx approaches

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yyxxy=

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x gets

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For example, consider this graph of the polynomial function

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f(x)→+∞

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5 0

3 years ago

Show that:sin60=2tan60/1+tan²60​

Show that:sin60=2tan60/1+tan²60