Answer:
The inverse of the function is ![f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-16%7D%7B8%7D%7D)
Step-by-step explanation:
Inverse of a function:
Suppose we have a function y = g(x). To find the inverse, we exchange the values of x and y, and then isolate y.
In this question:

Exchanging x and y:



![y = \sqrt[3]{\frac{x-16}{8}}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-16%7D%7B8%7D%7D)
The inverse of the function is ![f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-16%7D%7B8%7D%7D)
C = 3
You isolate the variable by dividing each side by factors that don’t contain the variable
Answer:
y + 13 = 5(x + 2)
Step-by-step explanation:
The slope-intercept form of the equation of a line is
y = mx + b,
where m = slope, and b = y-intercept.
From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.
The point-slope form of the equation of a line is:
y - y1 = m(x - x1)
where m = slope, and (x1, y1) is a point on the line.
We have point (-2, -13), so x1 = -2, and y1 = -13.
We also have slope 5, so m = 5.
Now we use the coordinates of the given point and the slope in the point-slope equation.
y - (-13) = 5(x - (-2))
We simplify to get
y + 13 = 5(x + 2)
Answer:
y = 2
Step-by-step explanation:
Both points are on the horizontal line ...
y = 2
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<em>Additional comment</em>
A horizontal line has equation y = constant. A vertical line has equation x = constant.
Answer:
The triangle A B C will be the image of triangle of A B C in origin (0,0)