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qwelly [4]
2 years ago
12

Pls help me I don’t understand this

Mathematics
2 answers:
MrRissso [65]2 years ago
5 0

Answer:

understand what? there's nothing there..

I am Lyosha [343]2 years ago
3 0
You didn’t put a question
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What is the inverse of the function g(x)=x^3/8+16
shtirl [24]

Answer:

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

Step-by-step explanation:

Inverse of a function:

Suppose we have a function y = g(x). To find the inverse, we exchange the values of x and y, and then isolate y.

In this question:

y = \frac{x^3}{8} + 16

Exchanging x and y:

x = \frac{y^3}{8} + 16

\frac{y^3}{8} = x - 16

y^3 = \frac{x-16}{8}

y = \sqrt[3]{\frac{x-16}{8}}

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

7 0
3 years ago
Solve for c.<br><br>Give an exact answer.<br><br><br>0.2(10−5c)=5c−16
Zielflug [23.3K]
C = 3
You isolate the variable by dividing each side by factors that don’t contain the variable
5 0
3 years ago
I watched a video and didn't get my free answer, can I have some help,
vazorg [7]

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

The slope-intercept form of the equation of a line is

y = mx + b,

where m = slope, and b = y-intercept.

From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.

The point-slope form of the equation of a line is:

y - y1 = m(x - x1)

where m = slope, and (x1, y1) is a point on the line.

We have point (-2, -13), so x1 = -2, and y1 = -13.

We also have slope 5, so m = 5.

Now we use the coordinates of the given point and the slope in the point-slope equation.

y - (-13) = 5(x - (-2))

We simplify to get

y + 13 = 5(x + 2)

8 0
2 years ago
The equation of the line pass through the points (-4,2) and (-5,2) is
ivanzaharov [21]

Answer:

  y = 2

Step-by-step explanation:

Both points are on the horizontal line ...

  y = 2

__

<em>Additional comment</em>

A horizontal line has equation y = constant. A vertical line has equation x = constant.

7 0
2 years ago
Read 2 more answers
Triangle A’ B’ C’ is the image of triangle A B C under a rotation about the origin, (0,0)
S_A_V [24]

Answer:

The triangle A B C will be the image of triangle of A B C in origin (0,0)

8 0
2 years ago
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