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2 years ago

Arrange the number in order from greatest to least square root 250, 11 4/9, 4 pie

1 answer:

3 0

$\bf \begin{array}{llll} \boxed{250} \\\\\\ 11+\frac{4}{9}\implies 11+0.\overline{44}\implies \boxed{11.\overline{44}} \\\\\\ 4\pi ~~\approx ~~\boxed{12.57} \end{array}~\hspace{3em} \begin{array}{|c|c|ll} \cline{1-1} \textit{from greatest to least}\\\cline{1-1}\\ 250\\ 12.57\\ 11.\overline{44}\\\cline{1-1} \end{array}$

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Dennis_Churaev [7]

Answer:

D^1 should be (28,0)

Step-by-step explanation:

a dilation is performed by multiplying the x and y coordinates by the scale factor. D(7,0)... (7×4,0×4).... D^1(28,0)

4 0

3 years ago

100 Points | Giving Brainliest to correct answer | Reporting false answers |

soldier1979 [14.2K]

Answer:

1.12/30 which is equals to 2/5

2.9 more students

3.171*1.50 =$25.65

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A game has a circular playing area in which you must hit a ball into a circular hole. The area of the playing area is 16ft2. The

Bad White [126]

Answer:

$4.9\%$

Step-by-step explanation:

we know that

To find out the probability of hitting a ball into the circular hole, divide the area of the hole by the area of the playing area

Let

x ----> the area of the hole

y ----> the area of the playing game

$P=\frac{x}{y}$

we have

$y=16\ ft^2$

Find the area of the hole

The area of the circle (hole) is equal to

$A=\pi r^{2}$

we have

$r=1/2=0.5\ ft$ ----> the radius is half the diameter

assume

$\pi =3.14$

substitute

$A=(3.14)(0.5)^{2}$

$A=0.785\ ft^2$

Find the probability

$P=\frac{x}{y}$

we have

$x=0.785\ ft^2$

$y=16\ ft^2$

substitute

$P=\frac{0.785}{16}$

$P=0.0491$

Convert to percentage

$0.0491*100=4.91\%$

Round to the nearest tenth

$4.9\%$

5 0

3 years ago

A right triangle has legs measuring 4.5 meters and 1.5 meters. The lenghts of the legs of a second triangle are proportional to

Eduardwww [97]

We know that
in the first triangle
the ratio of the legs are
4.5/1.5-----> 3

then
case A) 6 m and 2 m ------> ratio=6/3----> 3
so
the legs of a second triangle are proportional to the lengths of the legs of the first triangle

case B) 8 m and 5 m ------> ratio=8/5---->1.6
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle

case C) 7 m and 3.5 mm ------> ratio=7/3.5---->2
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle

case D) 10 m and 2.5 m ------> ratio=10/2.5---->4
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle

case E) 11.25 m and 3.75 m ------> ratio=11.25/3.75---->3
so
the legs of a second triangle are proportional to the lengths of the legs of the first triangle

the answer is
A) 6 m and 2 m
E) 11.25 m and 3.75 m

4 0

3 years ago

How to do this problem because it's hard

Elenna [48]

You will need to set up and solve 2 equations:
A) 3 Vans + 10 Buses = 379
B) 14Vans + 13 Buses = 624
Multiply equation A by -14
A) -42 Vans -140 Buses = -5,306 then Multiply equation B by 3
B) 42 Vans + 39 Buses = 1,872
Adding BOTH equations
-101 Buses = -3,434
Each Bus holds 34 Students

Putting this into equation A
A) 3 Vans + 10 Buses = 379
A) 3 Vans + 10 * 34 = 379
A) 3 Vans +340 = 379
A) 3 Vans = 39
Each van = 13 students

4 0

3 years ago