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2 years ago

11

For his long distance phone service, Juan pays a $5 monthly fee plus 9 cents per minute. Last month, Juan's long distance bill w

as $12.28 . For how many minutes was Juan billed?

1 answer:

Lera25 [3.4K]2 years ago

4 0

Answer:

80 or 81 minutes

Step-by-step explanation:

12.28-5 =7.28 7.28/.09= 80.88

You might be interested in

What does not represent the quotient of 17 divided by 10?

JulijaS [17]

Answer:

C

Step-by-step explanation:

The quotient of 17 divided by 10 is the fraction 17/10 or simplified 1 7/10, 1.7 or 1 R 7. It is NOT 10 / 17. C is the correct answer since it does not represent the quotient described.

6 0

2 years ago

Find the area of the shaded region.<br> 8 in<br> 24 in

zloy xaker [14]

Answer:

96 in^2

Step-by-step explanation:

area of rectangle: 24*8=192

Area of triangle: (1/2)*base*height

= .5 * 8 * 24

=192/2

=96

area of shaded=rectangle - triangle

= 192-96

which is also just 192/2

so it is 96

4 0

2 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

(15 points) what steps do i take to determine if y+3x^3=9 is linear

Annette [7]

Answer:

Answers are below

Step-by-step explanation:

Step 1: Graph the function

Step 2: Identify the type of function. This can be done by looking the exponents

Step 3: Since the exponent is 3, the function is not linear, but instead a cubic function.

I graphed this equation below.

If this answer is correct, please make me Brainliest.

3 0

3 years ago

Read 2 more answers

1/29+12/58+12/29=

irakobra [83]

Just find a common denominator and find the smallest number that goes into it, which in this case it is 29, so
1/29+6/29+12/29=19/29

5 0

3 years ago