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3 years ago

Write the expression in complete factored form. 4c(y+3) - (y+3)=

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

8 0

Answer:

(4c-1)(y+3)

Step-by-step explanation:

4c(y+3) -(y+3)

=(4c-1)(y+3)

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There are approximately 2.6 million deaths per year in country A. Express this quantity as deaths per minute.

igor_vitrenko [27]

Take 2.7 million divided by the number of minutes in a year. 1 hour= 60 minutes 1 day= 24 hours So you take 24 hours × 60 minutes =1440 minutes 1 year= 365 per minute.

7 0

3 years ago

Read 2 more answers

15 points please help :")

Liono4ka [1.6K]

Answer:

15*C

Step-by-step explanation:

The temperature rises by 2.4 every 3 cycles per second. So you would have to keep the pattern going.

6 cycles p/second = 19.8*C

3 cycles p/second = 17.4*C

0 cycles p/second = 15.0*C

So, because 0 cycles means the engine is resting, 15*C would be the answer.

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3 years ago

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A parallelogram has sides of length 19 mm, 19 mm, and 7 mm. What is the length of the fourth side of the parallelogram? Enter yo

liberstina [14]

Answer:

7mm

Step-by-step explanation:

A parallelogram has 2 sets of equal sides, so if one side is 7mm, then the opposite side is too.

5 0

3 years ago

14/5 + - 4/3 = Adding and Subtracting Fractions.

Helga [31]

Answer:

Step-by-step explanation:

$1 \frac{7}{15}$

6 0

2 years ago

In 2009, there were 1570 bears in a wildlife refuge. In 2010, the population had increased to

natita [175]

Answer:

$8,101\ bears$

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

x ----> is the number of years since 2009

y ----> is the population of bears

a ----> is the initial value

b ---> is the base

step 1

Find the value of a

For x=0 (year 2009)

y=1,570 bears

substitute

$1.570=a(b)^{0}$

$a=1.570\ bears$

$y=1.570(b)^{x}$

step 2

Find the value of b

For x=1 (year 2010)

y=1,884 bears

substitute

$1,884=1.570(b)^{1}$

$b=1,884/1.570$

$b=1.2$

The exponential function is equal to

$y=1.570(1.2)^{x}$

step 3

How many bears will there be in 2018?

2018-2009=9 years

For x=9 years

substitute in the equation

$y=1.570(1.2)^{9}$

$y=8,101\ bears$

7 0

3 years ago