If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.
n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?
The slope of the line as shown in the graph attached is 7/3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
A variable can either be independent or dependent. A dependent variable depends on other variable while an independent variable does not depend on other variable.
A linear equation is in the form:
y = mx + b
Where m is the rate of change (slope) and b is the y intercept.
The slope of a line = vertical rise / horizontal run
From the image:
Slope = rise / run = 7/3
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Answer:
The measure of variability should be used.
Step-by-step explanation:
It is provided that Rickie played eight rounds of miniature golf in June and eight rounds of miniature golf in July. He recorded the cores for each round.
Now to determine in which month Rickie's score varied the most the measure of variability would be used and not measure of center.
This is because:
The Measures of Central tendency is a distinct value that describe a data set by recognizing the central location within that data set. The measures of central tendency are every so often are known as measures of central location. They are also known as summary statistics.
Whereas the measure of variability is used to determine the amount of variability in the data set. They represent how far the observations are from the center of the data set.
Thus, to answer his mother's question, the measure of variability should be used.
Answer:
$73.89
Step-by-step explanation:
We have been given that Kathy Parker's employer pays 65% of the total cost of her $5,489 health insurance premium.
This means Kathy pays 35% of her health insurance premium.
Let us find 35% of $5489.
As we are asked to find Cathy's biweekly deduction for the insurance we will divide amount of premium paid by Cathy by 26 as biweekly is paid 26 times per year.
Therefore, Cathy's biweekly deduction for the insurance is $73.89.
