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IceJOKER [234]
3 years ago
14

90% of a number is x . What is 100% of the number? Assume x>0

Mathematics
1 answer:
mariarad [96]3 years ago
3 0

Step-by-step explanation:

Let the required number be n

\therefore \:  \frac{90}{100}  \times n = x \\  \\ \therefore \:  \frac{9}{10}   \\  \\  \therefore \:n = \frac{10}{9} x \\  \\  \therefore 100\% \: of\:n = \frac{10}{9} x \times 100\% \\  \\  = \frac{10}{9} x \times \frac{100}{100}  \\  \\  =  \frac{10}{9} x  \\

NOTE: A number is always 100% in itself.

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For each set of probabilities, determine whether the events A and B are independent or dependent.
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Answers:

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========================================================

Explanation:

If events A and B are independent, then the two following equations must both be true

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This is because the conditional probability P(A|B) means "P(A) when B has happened". If B were to happen, then P(A) must be the same as before. In other words, event B does not affect A, and vice versa.

For part (a), we have P(B) = 1/4 and P(B|A) = 1/4 showing that P(B|A) = P(B) is true, and therefore we can say the events are independent. We don't need the info that P(A) = 1/8.

------------------------

Unlike part (a), part (b) has the answer "dependent" because P(A) = 1/8 and P(A | B) = 1/3 differ in value. Event A starts off at probability 1/8, but then event B occurring means P(A) gets increased to 1/3. The prior knowledge about B changes the chances of A. The P(B) = 1/5 is unneeded.

------------------------

If A and B were independent, then,

P(A and B) = P(A)*P(B)

However,

P(A)*P(B) = (1/4)*(1/5) = 1/20

which is not the same as P(A and B) = 1/6. Therefore the two events are dependent.

------------------------

Refer back to part (a)

P(A) = 1/4 and P(A|B) = 1/4 are identical in value, so P(A|B) = P(A) which leads to the events being independent. Whether we know event B happened or not, it does not affect the outcome of event A. P(B) = 1/9 is unneeded.

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