Let x = number of 5 cent coins.
Then there are (x+2) 10 cent coins.
Let y = 20 cent coins.
Total coins: x+(x+2)+y = 30
2x+y=28
y = 28-2x (1)
Total value: 0.05x + 0.1(x+2) + 0.2y = 3.80
0.15x + 0.2y + 0.2 = 3.80
0.15x + 0.2y = 3.60 (2)
Substitute (1) into (2).
0.15x + 0.2(28-2x) = 3.60
-0.25x + 5.60 = 3.60
2.00 = 0.25x
8 = x
From (1), obtain y = 28 - 2(8) = 12
Answer: (x+2) = 8+2 = 10
Louise has 10 10-cent coins
6/30 as a decimal is 0.2
This is because if you divide 30÷6, you will get 0.6
Hope this helps
Using the Pythagorean theorem we can solve for x.
x^2 + 6^2 = 10^2
Simplify:
x^2 + 36 = 100
Subtract 36 from both sides:
x^2 = 64
x = √64
x = 8
The answer is the question of the answer is the question of whether the question is tow
