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hammer [34]
3 years ago
9

Please help!! i have no clue what to do and this packet is due tonight.

Mathematics
1 answer:
Stels [109]3 years ago
7 0

Answer:

[D] ∞

General Formulas and Concepts:

<u>Calculus</u>

Limits

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle  \lim_{n \to \infty} s(n)<em />

<em />\displaystyle s(n) = (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)<em />

<em />

<u>Step 2: Evaluate</u>

  1. Substitute in function [Limit]:                                                                           \displaystyle  \lim_{n \to \infty} (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)
  2. Multiply:                                                                                                             \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4}
  3. Power Method:                                                                                                 \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4} = \infty

Since the degree of the polynomial is greater in the numerator than in the denominator, the top will always increase faster than the bottom, thus getting infinitely larger.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

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