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3 years ago

What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Mathematics

2 answers:

timurjin [86]3 years ago

8 0

The answer is point V

vivado [14]3 years ago

7 0

Answer:

I believe that the answer would be the letter X. The Y units always go left and right (right if positive, left if negative) and the X units always go up and down (up if positive, down if negative).

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The perimeter of a triangle is 21. The smallest side is 3. The 2nd side is twice the smallest side. The 3rd side is 6 more than

svet-max [94.6K]

Answer:

Step-by-step explanation:

Area is measured in square units. For example in the rectangle above, if the sides are 2 and 4 meters long, then the area is 8 square meters. If the sides were 2 feet and 4 feet long the area would be 8 square feet. The most important thing to remember when calculating area is that.

5 0

3 years ago

Sean has some candy bars that he wants to give away. He is going to give each person \dfrac18 8 1 start fraction, 1, divided b

Afina-wow [57]

Answer:

22 people

Step-by-step explanation:

Sean has 2 3/4 candy bars. That is 11/4 candy bars.

He wants to give out 1/8 candy bars.

The number of people that will get candy is:

$\frac{11}{4} / \frac{1}{8}\\ \\= \frac{\frac{11}{4} }{\frac{1}{8}} \\\\\frac{11}{4} * \frac{8}{1} \\\\22$

22 people can get candy.

8 0

3 years ago

Read 2 more answers

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Lostsunrise [7]

Jayne will need to drive 40 mph on the way back.

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3 years ago

Based on the Empirical Rule, what percent of the data would fall AFTER the first standard deviation GREATER than the mean?

Tcecarenko [31]

13.5% i thinkkkkkkkkkk

4 0

3 years ago

Researchers studying starfish collected two independent random samples of 40 starfish. One sample came from an ocean area in the

krek1111 [17]

Answer:

The test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

H₀: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ = p₂.

Hₐ: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ ≠ p₂.

The two-proportion z-test would be used to perform the test.

A sample of n = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

$\hat p_{n}=\frac{6}{40}=0.15$

Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

$\hat p_{s}=\frac{11}{40}=0.275$

The test statistic is:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

Compute the combined proportion P as follows:

$P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125$

Compute the test statistic value as follows:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

$=\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$

Thus, the test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

8 0

3 years ago