Answer/Step-by-step explanation:
First, find the slope (m) of Line L using the points (0, 5) and (2, 1):
Slope (m) = -2
✔️Since the line is parallel bro Line L, it would also have the same slope value of -2.
We can use the slope (m) and a point (a, b) of the line to find its equation using the point-slope formula, y - b = m(x - a).
Substitute (a, b) = (3, 0), and m = -2 into y - b = m(x + a):
Thus,
✅y - 0 = -2(x + 3)
Rewrite equation in slope-intercept form
y = -2(x + 3)
✅y = -2x - 6
Answer:
16
Step-by-step explanation:
The existence of the constant rate of change is given the ratio of y to x is the same. Then:
In consequence, the constant rate of change is 16.
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I =
Area of ΔADC =
=
=
=
=
= 30 cm²
Area of equilateral triangle II =
Area of equilateral triangle II =
=
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH =
Since, GH = GJ + JK + KH
17 =
12 =
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² +
-81 = -x² +
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV =
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
