The perimeter of a rectangular garden is 44 meters. The length of the rectangle is 5 less than twice the width. Find the length and width of the rectangle. please helppp
1 answer:
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Answer:
Step-by-step explanation:
Let w represent the width. Then the length is 2w-5, and the perimeter is ...
P = 2(L+W)
44 = 2((2w-5) +w)
44 = 6w -10
54 = 6w
9 = w
2(9) -5 = 13 = length
The length of the rectangle is 13 meters; the width is 9 meters .
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Here are the graphs
CB is equal to 10m you can tell this bye the side DC being 20 m and the angle of DC is half of CB so that means that CB has to be 10 m
3 + 4x - 3x = 4 is given
3 + x = 4 is combine like terms (4x and -3x were combined to 1x)
x = 1 is subtraction property of equality (3 was subtracted from both sides of the equation)