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Scilla [17]
3 years ago
11

Find the perimeter of a rectangle with sides 3x + 6 and -2x -8​

Mathematics
2 answers:
patriot [66]3 years ago
5 0

Answer:

The perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:

P = 2x - 4

Step-by-step explanation:

We know that the perimeter of a rectangle of length 'l' and width 'w' is given by the formula

  • P = 2(length + width)

Given the sides of a rectangle

  • 3x + 6
  • -2x - 8​

As the opposite sides of a rectangle are congruent.

Therefore, we conclude that the Perimeter of a rectangle can be determined using the formula

\:P\:=\:2\left(3x\:+\:6\:+\:\left(-2x\:-\:8\right)\right)

    =2\left(3x+6-2x-8\right)

    =2\left(x-2\right)

     =2x-4

Therefore, the perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:

P = 2x - 4

vazorg [7]3 years ago
3 0

Answer:

2x - 4

Step-by-step explanation:

2(3x + 6) = 6x + 12

2(-2x - 8) = -4x -16

6x + 12 - 4x - 16 = 2x - 4

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The correct option is b. No, it is not a rectangle because the sides of the parallelogram do not meet at right angles.

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2(x + 3)+ 8 + 5(x - 2) + 4x + 3 This problem simplified would be:
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<span>simplified would be
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2(x + 3)+ 8 + 5(x - 2) + 4x + 3 
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