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Diano4ka-milaya [45]
3 years ago
8

Edwin runs two laps in 12 minutes.

Mathematics
2 answers:
blagie [28]3 years ago
8 0

Answer:6 minutes a lap

for 3 laps = 18

Step-by-step explanation:

12/2 = 6

6 times 3 = 18

Verdich [7]3 years ago
6 0
Well 12 divided by 2 is 6

6 is the unit rate so it would take 6 mins to run one lap.

I’m one hour, he could run 10 laps.

So... it would take 18 minutes to run 3 laps.
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3 years ago
John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time, the sum of their ages
oksano4ka [1.4K]

Answer:

8 years

Step-by-step explanation:

Let age of father be f

age of John be j

age of Alice be a

John's father is 5 times as old as John. We can write:

f = 5j

John is twice as old as Alice. We can write:

j = 2a

or

a = j/2

SUM OF ALL OF THEIR AGES (after 2 years) will be 58. We can write:

f+2 + j+2 + a+2 = 58

This becomes:

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Now, we replace third equation with the first two (in bold) and get:

f + j + a = 52\\5j + j + \frac{1}{2}j=52\\6.5j=52\\j=8

So John is 8 years old

7 0
3 years ago
In the accompanying diagram, PA is tangent to the circle at A and PC is a secant. If
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Answer:

c. 12

Step-by-step explanation:

PA² = (BC + PB) × PB => tangent-secant theorem

PA = 8

PB = 4

BC = ?

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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I am joyous to assist you anytime.

8 0
3 years ago
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