The correct solution to the limits of x in the tiles can be seen below.
- = -31
<h3>What are the corresponding limits of x?</h3>
The limits of x approaching a given number of a quadratic equation can be determined by knowing the value of x at that given number and substituting the value of x into the quadratic equation.
From the given diagram, we have:
1.
So, x - 9 is positive when x → 9⁺. Therefore, |x -9) = x - 9
Simplifying the quadratic equation, we have:
Replacing the value of x = 9
2.
- -x²-63x+568 is positive when x → 8⁻.
Thus |-x²-63x+568| = -x²-63x+568
3.
- x -7 is positive, therefore |x-7| = x - 7
= -31
4.
- x-6 is negative when x → 6⁻. Therefore, |x-6| = -x + 6
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Answer:
x = -3
i explained it in the picture
Answer:
y = 10x - 58
Step-by-step explanation:
y-y1 = m (x-x1)
m= 10
x1= 6
y1 = 2
y - 2 = 10 ( x - 6)
y - 2 = 10x -60
y = 10x - 58
Answer:
Step-by-step explanation:
Take a look at the place value chart.
A. Is a whole number, so it would be to the left of the decimal place. The 4 is in the thousands place.
B. Looking at the chart, B is .738 noticed that the 7 is in the tenths place.
C. The 2 is in the tenths place.
D. The 1 is in the tenths place.
Therefore the answer is B.
Please memorize this chart. It's going to be important for everything you do in math.
Answer:
5
Step-by-step explanation:
We know that a^b^c = a^(b*c)
5 ^ 1/3 ^3
5^(1/3*3)
5^1
5