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3 years ago

If a star is measured to have a parallax angle of 0.5 arcsec, how far away is the star?

Mathematics

1 answer:

blagie [28]3 years ago

5 0

I think it’s a (b) because that one makes sence

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Can any kind soul help me please

bezimeni [28]

Answer:

p-q= -4

p=q-4

x^2 + px + q=0

=> x^2 + (q-4)x + q = 0

d= b^2-4ac

=(q-4)^2 - 4(1)(q)

= q^2 + 16 -8q - 4q

=q^2 -12q+16

given that D=16

q^2 -12q+16 = 16

=> q^2 -12q = 0

=> q^2 = 12q

=> q = 12q/q

=> q= 12

Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8

Hope you understood............

6 0

3 years ago

Ray and Kelsey are working to graph a third-degree polynomial function that represents the first pattern in the coaster plan. Ra

DENIUS [597]

Hints:
Intercepts could mean either x-intercept or y-intercept.
3 zeroes means three x-intercepts.

5 0

3 years ago

Read 2 more answers

he box plot represents the number of minutes it takes for the students in a class to run a mile. What is the minimum of the data

Elis [28]

It's 5. Just took this test and got this question right :)

7 0

4 years ago

Read 2 more answers

In 1993, president Clinton received an average of 25,000 letters per day. How many letters did he receive during the entire year

rusak2 [61]

Answer:

9,125,000

Step-by-step explanation:

25,000 x 365 days in a year = 9,125,000

5 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago