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pishuonlain [190]
3 years ago
13

A truck is carrying grapefruit juice, pineapple juice, and tomato juice bottles in a ratio of 3 : 1 : 2. If there are 14 pineapp

le juice bottles, then how many juice bottles in total are there?
Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

84 juice bottles

Step-by-step explanation:

Given the ratio of grapefruit juice, pineapple juice, and tomato juice bottles as

3:1:2

Let the total number of bottles available be R

If there are 14 pineapple juice bottles, then

1/(3 + 1 + 2) * R = 14

1/6 * R = 14

multiply both sides by 6

R = 14 * 6

= 84

This means there are 84 bottles in all

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mel-nik [20]
Answer: x= log18 (10) +1/2
x= 1.29664

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3 years ago
3 1/2 covert to ounces
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3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
A rounded scoop of ice cream<br> is put onto a cone so that half<br> of it is in the cone.
Len [333]

Answer:

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Step-by-step explanation:

First, we find volume of hemisphere, then find the volume of the cone, once we get those, we add them together and find our final answer. I hope this helps :)

7 0
2 years ago
If 43 of the 148 reams of paper purchased by a department are used, what is the percentage that remains?
Wewaii [24]
100%/x%=148/43
<span>(100/x)*x=(148/43)*x       - </span>we multiply both sides of the equation by x
<span>100=3.44186046512*x       - </span>we divide both sides of the equation by (3.44186046512) to get x
<span>100/3.44186046512=x </span>
<span>29.0540540541=x </span>
<span>x=29.0540540541

</span>now we have: 
<span>43 is 29.0540540541% of 148</span>
3 0
3 years ago
Read 2 more answers
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