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max2010maxim [7]

3 years ago

14

Please solve

=100" align="absmiddle" class="latex-formula"> Thank you

1 answer:

mel-nik [20]3 years ago

8 0

Answer: x= log18 (10) +1/2
x= 1.29664

Good luck !

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The answers to these questions please

vfiekz [6]

Answer:

Q10 is 13.64 cm3

Q 11 is 221 cm3

Step-by-step explanation:

volume is cross sectional area times height for Q 10

volume is length times width times height for Q 11

5 0

3 years ago

_ 4. How many roots does the following equation have: 2x^4 – x^3 – 12x^2 – 25x + 5 = 0

vlada-n [284]

Answer:

B. 4

Step-by-step explanation:

The degree of the polynomial (the exponent of the highest term) is the total number of roots (including imaginary roots).

The degree of this polynomial is 4, so there are 4 roots.

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3 years ago

Maria wrote the equation of a line that has a slope of 4/3

ExtremeBDS [4]

Answer:

The equation of the line is y=4/3x+1

Step-by-step explanation:

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2 years ago

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Henry bought 4 pies, which he plans to share with a group of his friends. If there is exactly enough to give each

Cloud [144]

Answer:

Step-by-step explanation:

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8 0

2 years ago

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Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

1 year ago