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Ne4ueva [31]
3 years ago
15

If 43 of the 148 reams of paper purchased by a department are used, what is the percentage that remains?

Mathematics
2 answers:
Wewaii [24]3 years ago
3 0
100%/x%=148/43
<span>(100/x)*x=(148/43)*x       - </span>we multiply both sides of the equation by x
<span>100=3.44186046512*x       - </span>we divide both sides of the equation by (3.44186046512) to get x
<span>100/3.44186046512=x </span>
<span>29.0540540541=x </span>
<span>x=29.0540540541

</span>now we have: 
<span>43 is 29.0540540541% of 148</span>
dusya [7]3 years ago
3 0
First, calculate how many reams remain
remaining = 148 - 43
remaining = 105
There are 105 reams of paper remains

Second, change 105 reams into percentage
p = \dfrac{105}{148} \times 100 \%
p = \left(\dfrac{105 \times 100}{148}\right) \%
p = \left(\dfrac{10,500}{148}\right) \%
p = 70.945945945...%
to the nearest tenth
p = 70.9%

The percentage of paper remains is approximately 70.9%
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Answer:

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Step-by-step explanation:

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Where; b is its base and h the height.

Thus,

a. The ratio of the area of the two triangles is:

\frac{area of the smaller triangle}{area of the larger triangle}

Area of smaller triangle = \frac{1}{2} x b x h

                                       = \frac{1}{2} x 5 x h

                                       = \frac{5}{2}h

Area of the lager triangle = \frac{1}{2} x b x h

                                           = \frac{1}{2} x 8 x h

                                           = 4h

So that;

Ratio = \frac{\frac{5}{2}h }{4h}

         = \frac{5}{8}

The ratio of the areas of the two triangles is 5:8.

b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;

\frac{area of the smaller triangle}{area of the larger triangle} = \frac{5}{8}

\frac{15}{A_{2} } = \frac{5}{8}

5 A_{2} = 15 x 8

       = 120

A_{2} = \frac{120}{5}

    = 24

The area of the larger triangle is 24 in².

         

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