Let's explore possible case scenarios.
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Case A) Each person gets a rose and a daisy (2 flowers per person)
In this case, Jackie can make 2 such arrangements because she has 2 roses. We have 2 left over daisies.
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Case B) Each person gets a rose only (1 flower per person)
Only two arrangements are possible for the same reason as case A. In this situation, we have 4 left over daisies.
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Case C) Each person gets a daisy only (1 flower per person)
We have 4 arrangements possible because we have 4 daisies. The left over flowers are the 2 roses.
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Case D) Each person gets 2 roses
Only one such arrangement is possible, so this only applies to one person really. You can say that 2/2 = 1. We have 4 left over daisies in this case.
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Case E) Each person gets 2 daisies
Since 4/2 = 2, this means we can make 2 arrangements. There are 2 left over roses.
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Case F) Each person gets 2 daisies and 1 rose
We can see that 4/2 = 2 and 2/2 = 1, meaning that we can make at most 2 arrangements here. There are no leftovers. In contrast, the other cases do have leftovers of some kind.
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In short, you can do trial and error to see which case works to fit the conditions your teacher set. Case F is what we go for to have each flower bouquet consist of 2 daisies and 1 rose. We'll get 2 bouquets possible. Notice how cases A through E have at least one left over flower (either of one kind or both types), while case F has no leftovers.
you have to put two points (x, y): (-2, 0) and (0, -4). Then just draw the line across these points like that: