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2 years ago

Write a balanced chemical equation showing how each metal oxide reacts with HCl.

Chemistry

1 answer:

larisa86 [58]2 years ago

3 0

Answer:

ZnO(s) + 2HCl(aq) ------> ZnCl2(aq) + H2O(l)

Na2O(s) + 2HCl(aq) -----> 2NaCl(aq) + H2O(l)

Rb2O(s) + 2HCl(aq) -----> 2RbCl(aq) + H2O(l)

NiO(s) + 2HCl(aq) --------> NiCl2(aq) + H2O(l)

MgO(s) + 2HI(aq) -----> MgI2(aq) + H2O(l)

Na2O(s) + 2HI(aq) -----> 2NaI(aq) + H2O(l)

CaO(s) + 2HI(aq) ----> CaI2(aq) + H2O(l)

Explanation:

Let us recall that the oxides of metals are basic in nature. These basic metal oxides can react with acids to form salt and water only.

In the reactions above, HCl and HI were reacted with different metal oxides and the corresponding salts of each metal and water was formed as shown.

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2 years ago

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Tju [1.3M]

Answer:

a) $\Delta S$

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

$\delta S=\frac{\delta Q}{T}$

$\Delta S=\frac{Q}{T}$

The energy balance:

$\delta U=[tex]\delta Q- \delta W$

If the process is isothermical the U doesn't change:

$0=[tex]\delta Q- \delta W$

$\delta Q= \delta W$

$Q= W$

The work:

$W=\int_{V1}^{V2}P*dV$

If it is an ideal gas:

$P=\frac{n*R*T}{V}$

$W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV$

Solving:

$W=n*R*T*ln(V2/V1)$

Replacing:

$\Delta S=\frac{n*R*T*ln(V2/V1)}{T}$

$\Delta S=n*R*ln(V2/V1)}$

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

$\Delta S$

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

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3 years ago