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PilotLPTM [1.2K]
3 years ago
8

Write a balanced chemical equation showing how each metal oxide reacts with HCl.

Chemistry
1 answer:
larisa86 [58]3 years ago
3 0

Answer:

ZnO(s) + 2HCl(aq) ------> ZnCl2(aq) + H2O(l)

Na2O(s) + 2HCl(aq) -----> 2NaCl(aq) + H2O(l)

Rb2O(s) + 2HCl(aq) -----> 2RbCl(aq) + H2O(l)

NiO(s) + 2HCl(aq) --------> NiCl2(aq) + H2O(l)

MgO(s) + 2HI(aq) -----> MgI2(aq) + H2O(l)

Na2O(s) + 2HI(aq) -----> 2NaI(aq) + H2O(l)

CaO(s) + 2HI(aq) ----> CaI2(aq) + H2O(l)

Explanation:

Let us recall that the oxides of metals are basic in nature. These basic metal oxides can react with acids to form salt and water only.

In the reactions above, HCl and HI were reacted with different metal oxides and the corresponding salts of each metal and water was formed as shown.

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Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?
Sindrei [870]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂   = 4 x 1 / 2

= 2  moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x  2

= 116 g of <span> Mg(OH)₂</span>

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Is 4 grams of oxygen bigger than 1 mole of oxygen
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No, a mole of oxygen is about 16 grams

Explanation:

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What is the chemical formula for iron (ii) oxide?​
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Explanation:

4 0
3 years ago
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A chemist wants to extract copper metal from copper chloride solution. The chemist places 1.50 grams of aluminum foil in a solut
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Answer: d. More than 6.5 grams of copper (II) is formed, and some copper chloride is left in the reaction mixture.

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As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of copper chloride.

According to mole concept, 1 mole of every substance weighs equal to its molar mass.

Aluminium is the limiting reagent as it limits the formation of product and copper chloride is the excess reagent as (14-7.5)=6.5 g is left as such.

Thus 54 g of of aluminium react with 270 g of copper chloride.

1.50 g of aluminium react with=\frac{270}{54}\times 1.50=7.5 gof copper chloride.

3 moles of copper chloride gives 3 moles of copper.

7.5 g of copper chloride gives 7.5 g of copper.

8 0
3 years ago
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