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3 years ago

I need the answer please and thank you worth 78 brainly points

Mathematics

1 answer:

Reika [66]3 years ago

5 0

Answer:

8+4pi

Step-by-step explanation:

2pi(r) = 8pi

8pi/2 = 4pi

8+4pi

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Alina [70]

Honestly I couldn't understand most of that but if one gallon of oil is needed to fry 6 potatoes, and he wants to fry 18 potatoes, then he'll end up using 3 gallons

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3 years ago

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Subtract one- fifth from seven times w

natulia [17]

We can write one fifth as $\frac{1}{5}$

7 times of w , we can write as = 7w

Now we have to subtract one fifth from seven times of w.

So we can write it in algebraic expression as

$7w - \frac{1}{5}$

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3 years ago

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zhenek [66]

Answer:

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Step-by-step explanation:

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3 years ago

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givi [52]

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Step-by-step explanation:

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4 years ago

Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation

murzikaleks [220]

Answer:

See explanation below

Step-by-step explanation:

<u>First we will solve the radical equation</u> (which I guess was problem 1),

Let's start by simplifying it:

$3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4$

Now we will solve the equation by squaring both sides of the equation:

$\sqrt{6-x} =-4\\6-x=-4^{2} \\6-x=16\\-x=16-6\\-x=10\\x=-10$

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

$3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8$

This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

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3 years ago