Step-by-step explanation:
For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).
1) y = -0.5t² + 2t + 38
The maximum is at:
t = -2 / (2 × -0.5)
t = 2
The maximum height is:
y = -0.5(2)² + 2(2) + 38
y = 40
The coordinates of the vertex are (2, 40). That means the missile reaches a maximum height of 40 km after 2 minutes.
2) y = -4.9t² + 12t + 1.6
The maximum is at:
t = -12 / (2 × -4.9)
t = 1.22
The maximum height is:
y = -4.9(1.22)² + 12(1.22) + 1.6
y = 8.95
The coordinates of the vertex are (1.22, 8.95). That means the missile reaches a maximum height of 8.95 m after 1.22 seconds.
3) y = -0.04x² + 0.88x
The maximum is at:
x = -0.88 / (2 × -0.04)
x = 11
The maximum height is:
y = -0.04(11)² + 0.88(11)
y = 4.84
The maximum height of the tunnel is 4.84 meters.
The maximum width is when y = 0.
0 = -0.04x² + 0.88x
0 = -0.04x (x − 22)
x = 22
The maximum width is 22 feet.
Answer:
Step-by-step explanation:
So, in this problem, we're given the size of the of the file. We are also given the rate of change of the amount-downloaded function.
Notice how the transfer rate is in units of time (25.2 MB/s means 25.2 MB per second).
If we want to calculate how <em>long</em> it'll take to download the entire file, we have to divide the file size by the amount of the MB downloaded in one second. (This is assuming the download rate is constant, in the case it isn't constant, you would use calculus) This will find the total number of seconds needed to download the entire file.
We're essentially solving for t in the equation
Answer:
c
Step-by-step explanation:
im pretty sure its c. every other one is wrong except a and c. and the placement for a is wrong. so i think c.
Answer:
clro sia
Step-by-step explanation:
Y=mx+b is slope intercept form. it is y=3x+2 where 3/1 is the slope and 2 is the y-intercept.
