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kotykmax [81]
3 years ago
12

Please help me with this

Mathematics
2 answers:
SashulF [63]3 years ago
8 0

Answer:

512

Step-by-step explanation:

2x2x2x2x2x2x2x2x2= 512

sleet_krkn [62]3 years ago
8 0
512! :) have a great day!
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Paws at play made a total of $1234 grooming 22 dogs. Paws at Play charges $43 to groom each small dog and $75 for each large dog
vitfil [10]

Answer:

<u>Answer (a):</u>

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

<u>Answer (b)</u>

9 large dogs.

Step-by-step explanation:

Paws at Play made a total of $1234 grooming 22 dogs.

Paws at Play charges $43 to groom each small dog and;

$75 for each large dog.

Let the number of small dogs be 's'

And the number of large dogs be 'l'

<u>A system of equations will be:</u>

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;

43s + 43l = 946 ... (i)

43s + 75l = 1234 ... (ii)

Subtracting (i) from (ii) we get;

32l = 288 , l = \frac{288}{32} = 9

So there are 9 large dogs.

8 0
3 years ago
Use compatible numbers to estimate the quotient.<br> 486/6
Sladkaya [172]
The answer is 81. You just have to do the division in the traditional way.

8 0
3 years ago
Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

5 0
3 years ago
4x squared times -3x ^-5 y squared
Ad libitum [116K]

Answer:

Rewrite this question

5 0
3 years ago
Please please someone help
natka813 [3]

The answer is the first one:

bc its not growing by a (-)1/2  and the 3rd one just doesnt make sense

7 0
3 years ago
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