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2 years ago

Lines

Mathematics

1 answer:

GuDViN [60]2 years ago

5 0

Answer: it is b

Step-by-step explanation:

i took the test boys

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Tomatoes are on sale for 3 lb for$1.09 how much wil 5 lb of tomatoes cost

jarptica [38.1K]

3lb/$1.09

3 3

1lb/$0.363

1lb x 5/ $0.363 x 5

Answer - 5lb/$1.815

4 0

2 years ago

What is the answer to this

klio [65]

Answer:

yes, the centroid is where the medians meet

hope this helps!

have a great day :)

3 0

2 years ago

Helppppppppppp please

LenaWriter [7]

Answer:

x = 60°

Step-by-step explanation:

AOB Center: O AB: diameter

arc ADB = 180°

arc DB = 180 - arc AD = 80°

x = 1/2 x ( arc DB + arc AC) = 1/2 x (80 + 40) = 60°

3 0

3 years ago

Please Help Me

Ymorist [56]

Answer:

81 m/s

Step-by-step explanation:

If the box is sliding at 27 m per second, and it's been sliding for 3 seconds, then you should multiply 3 × 27 and your answer would be 81 m/s

4 0

2 years ago

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

2 years ago