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3 years ago

Select the sentence that represents the equation below.

Mathematics

1 answer:

Alexeev081 [22]3 years ago

5 0

Answer:

Eight less than four times a number is equal to two times the difference of double that same number decreased by three.

Step-by-step explanation:

The given equation is:

4x−8=2(2x−3)

We will try to translate the given equation in English.

We can see that the variable used is only one. On the left hand side of the equation 8 is being subtracted from 4 times of the variable and on the right hand side 3 is being subtracted from 2 times of variable and then being multiplied by two.

From the given option, correct answer is:

Eight less than four times a number is equal to two times the difference of double that same number decreased by three.

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The circumference of a circle is 106.76 meters. What is the circle's diameter?

Flura [38]

C = 2*pi*r
So, C = pi*d
106.76 = pi*d
106.76/pi = d
d = ~33.98

5 0

3 years ago

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Simplify each expression using the proper order of operations. please help thank you so much :)

Tasya [4]

Answer:

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

$7^2 - 5* 8+1 = 10$

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

Step-by-step explanation:

<em>Required: Solve the expressions using proper operation order</em>

To solve this, we'll make use of BODMAS

--------------------------------------------------------------------------------------------------------

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26}$

Evaluate all squares and square roots

$\frac{41 - 3*3}{\sqrt{36} * 3 - 26}$

$\frac{41 - 3*3}{6 * 3 - 26}$

Evaluate the numerator (Start by multiplying 3 * 3)

$\frac{41 - 9}{6 * 3 - 26}$

Subtract 9 from 41

$\frac{32}{6 * 3 - 26}$

Evaluate the denominator (Start by multiplying 6 * 3)

$\frac{32}{18 - 26}$

$\frac{32}{-8}$

Divide 32 by -8

-4

Hence;

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

--------------------------------------------------------------------------------------------------------

$12 + 3\sqrt{8} * (9 - 2)$

Start by evaluating the bracket

$12 + 3\sqrt{8} * 7$

Then evaluate the multiplication

$12 + 21\sqrt{8}$

Simplify the square root

$12 + 21\sqrt{4 * 2}$

Split the square root

$12 + 21\sqrt{4} * \sqrt{2}$

Take Square root of 4

$12 + 21 * 2} * \sqrt{2}$

$12 + 42 \sqrt{2}$

Hence;

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

--------------------------------------------------------------------------------------------------------

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5}$

Evaluate 7²

$\frac{28 - (49 + 3)}{-13 + 3 * 5}$

Evaluate all expression in the bracket

$\frac{28 - (52)}{-13 + 3 * 5}$

$\frac{28 - 52}{-13 + 3 * 5}$

Evaluate 3 * 5

$\frac{28 - 52}{-13 + 1 5}$

$\frac{-2 4}{2}$

$-12$

Hence;

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

--------------------------------------------------------------------------------------------------------

$7^2 - 5* 8+1$

Evaluate 7²

$49 - 5* 8+1$

Evaluate 5 * 8

$49 - 40 + 1$

$10$

$7^2 - 5* 8+1 = 10$

--------------------------------------------------------------------------------------------------------

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1$

Evaluate all square root and cube root

$(2 * 4) - (3 * 9) + 1$

Solve the expressions in bracket

$8 - 27 + 1$

$-18$

Hence;

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

7 0

3 years ago

Determine the zero of F(x)=x^2+3x-5

IgorLugansk [536]

Answer:

The answer to your question is:

Step-by-step explanation:

x² + 3x - 5

x² + 3x + (3/2)² = 5 + (3/2)²

(x + 3/2)² = 5 + 9/4

(x + 3/2)² = (20 + 9) /4

(x + 3/2)² = 29/4

x + 3/2 = ±√29 / 2

x 1 = -3/2 + √29/2 x2 = -3/2 - √29/2

x1 = 1.19 x2 = -4.19

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3 years ago

Does anybody know how to do Factor with distribution property (Variables) ?

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Hope i was able to help

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3 years ago

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2 factors of 28 add up to 9 what are they

bogdanovich [222]

It is 2 and it is 7 the two factors your welcome

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3 years ago

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