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olchik [2.2K]
3 years ago
11

Given the linear equation 2x + y = 6, write another linear equation in two variables such that these two equations when represen

ted geometrically form parallel lines.
Mathematics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

The family of lines that are parallel to 2\cdot x + y = 6 is of the form 2\cdot x + y = k, \,k\neq 6. A possible solution is 2\cdot x + y = -2.

Step-by-step explanation:

Let be 2\cdot x + y = 6 the equation of a line, another line is parallel to it if and only if it is of the form:

2\cdot x + y = k, \,k\neq 6  (1)

Then, a possible solution is 2\cdot x + y = -2.

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Help<br> Consider function f. F(x) = ^3square8x + 4
mojhsa [17]

Answer:

f^{-1}(x)=\frac{1}{8}(x-4)^{3}

Step-by-step explanation:

Given function is,

f(x) = \sqrt[3]{8x}+4

To find the inverse of this function,

Rewrite the function as a equation,

y = \sqrt[3]{8x}+4

Interchange x by y and y by x,

x = \sqrt[3]{8y}+4

Now solve this equation for y,

x - 4 = \sqrt[3]{8y}

(x - 4)³ = (\sqrt[3]{8y})^3

(x - 4)³ = 8y

y = \frac{1}{8}(x-4)^{3}

Now convert the equation into function,

f^{-1}(x)=\frac{1}{8}(x-4)^{3}

3 0
3 years ago
Find the product of (x² - 5)² using identities​
timama [110]

Answer:

Step-by-step explanation:

by idetity : (a - b)²= a² +b² -2ab

for : (x² - 5)² you have  a = x²  and b = 5

(x² - 5)²= (x²)²+5² - 2(5)(x²)

(x² - 5)²= x^4+25 -10x²

6 0
3 years ago
Please help im in the bathroom doing my Alger fa because I don’t want to go in person
sweet-ann [11.9K]

Answer:

(8,-3)

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Two boats are travelling at 30 miles/hr, the first going north and the second going east. The second crosses the path of the fir
vampirchik [111]

Answer:

their distance is increasing at the rate of 41.6 miles/hr

Step-by-step explanation:

Given the data in the question;

first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;

⇒ ( 30/60 ) × 10 = 5 miles

so as illustrated in the diagram below;

y² = x² + ( x + 5 )²

2y\frac{dy}{dt} = 2x\frac{dx}{dt} + 2(x+5)\frac{dx}{dt}

y\frac{dy}{dt} = ( 2x + 5 ) ]\frac{dx}{dt}

\frac{dy}{dt} = [( 2x + 5 )/y ]\frac{dx}{dt}   ------ let this be equation 1

Now, given that, \frac{dx}{dt}  = 30 miles/hr, when x = 10

so

y = √( 10² + 15² ) = √325

so from equation 1

\frac{dy}{dt} = [( 2x + 5 )/y ]\frac{dx}{dt}

we substitute

\frac{dy}{dt} = [( 2(10) + 5 ) / √325 ]30

\frac{dy}{dt} = [ 25 / √325 ] × 30

\frac{dy}{dt} = 41.6 miles/hr

Therefore, their distance is increasing at the rate of 41.6 miles/hr

5 0
3 years ago
Which of the following inequalities is graphed below? 
Nonamiya [84]
It's D, because the slope is 3/5, and since the shaded area is above the line, y has to be greater than the other side of the inequality.
8 0
3 years ago
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