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____ [38]
3 years ago
5

If you put in 10 J of work to push 1 c of charge against and electric field what will be its voltage with respect to its startin

g position?when released, what will be it’s kinetic energy if it flies past it’s starting position?
Physics
1 answer:
pashok25 [27]3 years ago
3 0
It will have a value if 10V as a volt is a measurement of joules per charge so if there is 10j and 1c that makes 10V and since there is 10 J at its position using .5mv^2 we can solve this. First we find mass by knowing per electron it has a mass of 9.1E-31 kg and a charge is 1.6E-19C so we then divide 1C/1.6E-19 getting us roughly 6.2E18 electrons, then by multiplying the number of electrons by mass of an electron we get the total mass which is 5.642E-12kg. Now we can use the energy equation and plug in out mass so 10J=.5*(5.642E-12kg)*v^2. Then isolating v we end up with sqrt (2(10J)/5.642E-12kg)=V so V equals 3.5E12
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Can someone answer questions 1-3 please.
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Answer:

Question 1 is C.

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A book with a mass of 1.2 kg sits on a bookshelf. If it has gravitational potential energy of 50 j, how high is the shelf ? The
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B

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What would the resultant force be on an object that has a mass of 25 kg and is accelerated at a rate of 2.36 m/s^2?
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Answer:

resultant force = 59 N

Explanation:

we know the formula: <em>Force = mass * acceleration</em>

                                    Force = 25 kg  *   2.36 m/s²

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Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree
kvv77 [185]

Answer:

1

When second polarizer is removed the intensity after it passes through the stack is    

                    I_f_3 = 27.57 W/cm^2

2 When third  polarizer is removed the intensity after it passes through the stack is    

                I_f_2 = 102.24 W/cm^2

Explanation:

  From the question we are told that

       The angle of the second polarizing to the first is  \theta_2 = 21^o  

        The angle of the third  polarizing to the first is     \theta_3 = 61^o

        The unpolarized light after it pass through the polarizing stack   I_u = 60 W/cm^2

Let the initial intensity of the beam of light before polarization be I_p

Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as

                     I_1 = \frac{I_p}{2}

Now according to Malus’ law the  intensity of light that would emerge from the second polarizing filter is mathematically represented as

                    I_2 = I_1 cos^2 \theta_1

                       = \frac{I_p}{2} cos ^2 \theta_1

The intensity of light that will emerge from the third filter is mathematically represented as

                  I_3 = I_2 cos^2(\theta_2 - \theta_1 )

                          I_3= \frac{I_p}{2}(cos^2 \theta_1)[cos^2(\theta_2 - \theta_1)]

making I_p the subject of the formula

                  I_p = \frac{2L_3}{(cos^2 \theta [cos^2 (\theta_2 - \theta_1)])}

    Note that I_u = I_3 as I_3 is the last emerging intensity of light after it has pass through the polarizing stack

         Substituting values

                      I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (61-21)])}

                      I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (40)])}

                           =234.622W/cm^2

When the second    is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as

                      I_f_3 = \frac{I_p}{2} cos ^2 \theta_2

I_f_3 is the intensity of the light emerging from the stack

                     

substituting values

                     I_f_3 = \frac{234.622}{2} * cos^2(61)

                       I_f_3 = 27.57 W/cm^2

  When the third polarizer is removed  the  second polarizer becomes the

the final polarizer and the intensity of light emerging from the stack would be  

                  I_f_2 = \frac{I_p}{2} cos ^2 \theta_1

I_f_2 is the intensity of the light emerging from the stack

Substituting values

                  I_f_2 =  \frac{234.622}{2} cos^2 (21)

                     I_f_2 = 102.24 W/cm^2

   

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zloy xaker [14]

Answer:

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