The maximum height of the ball during this interval is 4.9 m (Option A)
<h3>How to determine the time to reach maximum height</h3>
The time taken to reach the maximum height can be obtained as follow:
- Time for the entire trip (T) = 2 s
- Time to reach maximum height (t) = ?
T = 2t
2 = 2t
Divide both side by 2
t = 2 / 2
t = 1 s
<h3>How to determine the maximum height reached by the ball</h3>
The maximum height reached by the ball can be obtained as follow:
- Acceleration due to gravity (g) = 9.8 m/s²
- Time to reach maximum height (t) =?
- Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 1²
h = ½ × 9.8 × 1
h = 4.9 m
Thus, the maximum height reached by the ball is 4.9 m (Option A)
Learn more about motion under gravity:
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Up ward direction...
Positive direction
Answer:
9.8m/s²
Explanation:
An object experiening a free fall is simply under the influence of gravity.
When an object is influenced by gravity, the object falls with an acceleration known as acceleration due to gravity.
This acceleration known as acceleration due to gravity has a constant value of 9.8m/s².
Answer:
0.05J
Explanation:
Since the total energy is conserved I.e the mechanical energy, the energy present in the system are kinetic energy, potential energy and the gravitational potential energy. The expression for this energy is written as
Kinetic Energy=1/2MV^2
Potential Energy=1/2Kx^2
Where K is the spring constant and X is the extension the spring experience.
Gravitational Energy=mgh
Where m=mass, g=gravity constant and h=height
Hence for a spring with spring constant 10N/m and extension 0.1m the potential energy can be calculated as
PE=1/2Kx^2
If we substitute values we arrive at
PE=1/2×10×0.1^2
PE=0.05J