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Brrunno [24]
3 years ago
13

Solve the following system of equations. 2x + y = 3 x = 2y - 1

Mathematics
2 answers:
RoseWind [281]3 years ago
8 0
Using the substitution method.

2x + y = 3
x = 2y -1                 Since x has been isolated already plug it into Equation 1 

2(2y - 1) + y = 3       Solve for y.
4y - 2 + y = 3
<u>    +2          +2 </u>          Combine like terms and isolate y.
4y + y  =  5
        5y = 5               Isolate y by dividing both sides by 5
5y/5  =   5/5
  y   =   1  

With y solved, solve either system for x.

x = 2(1) - 1
x = 2-1 
x = 1

Solution is (1,1)


Shalnov [3]3 years ago
7 0
2(2y-1)+y=3
y=1
x=2 x1 - 1
x=1
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5 0
3 years ago
F(x)=3x-3<br><br>g(x) 3x^3+5<br>Find F(-3) and g(-2)
astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is <em>x</em> = -3 for function f(x)

g(-2) is <em>x</em> = -2 for function g(x)

<u>Step 2: Evaluate</u>

f(-3)

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-3) = 3(-3) - 3
  2. Multiply:                                                                                                             f(-3) = -9 - 3
  3. Subtract:                                                                                                            f(-3) = -12

g(-2)

  1. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-2) = 3(-2)³ + 5
  2. Exponents:                                                                                                        g(-2) = 3(-8) + 5
  3. Multiply:                                                                                                            g(-2) = -24 + 5
  4. Add:                                                                                                                   g(-2) = -19
4 0
3 years ago
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What is the equation of a line that has a y-intercept of 4 and an x-intercept of -2?​
Furkat [3]

Answer:

y = 2x + 4

Step-by-step explanation:

Two points on this line are (-2, 0) and (0, 4).  Going from the first to the second, x increases by 2 (this is the 'run') and y increases by 4 ('rise').

Thus, the slope of this line is m = rise / run =  4/2 = 2

Using the slope-intercept formula, we get y = mx + b = 2x + b

Let x = -2 and y = 0 to find b:  0 = 2(-2) + b, so b = 4, and the desired equation is then:

y = 2x + 4

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The level of a lake in inches is falling linearly . The lake level is 452 inches on Jan 1 and then 378 inches on Jan 21. Find a
Marysya12 [62]

Answer:

y=-\frac{74}{21}x+452

Step-by-step explanation:

Given:

The level of a lake is falling linearly.

On Jan 1, the level is 452 inches

On Jan 21, the level is 378 inches.

Now, a linear function can be represented in the form:

y=mx+b

Where, 'm' is the rate of change and 'b' is initial level

x\to number\ of\ days\ passed\ since\ Jan\ 1

y\to Lake\ level

So, let Jan 1 corresponds to the initial level and thus b = 452 in

Now, the rate of change is given as the ratio of the change in level of lake to the number of days passed.

So, from Jan 1 to Jan 21, the days passed is 21.

Change in level = Level on Jan 21 - Level on Jan 1

Change in level = 378 in - 452 in = -74 in

Now, rate of change is given as:

m=\frac{-74}{21}

Hence, the function to represent the lake level is y=-\frac{74}{21}x+452

Where, 'x' is the number of days passed since Jan 1.

8 0
3 years ago
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