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Brrunno [24]
3 years ago
13

Solve the following system of equations. 2x + y = 3 x = 2y - 1

Mathematics
2 answers:
RoseWind [281]3 years ago
8 0
Using the substitution method.

2x + y = 3
x = 2y -1                 Since x has been isolated already plug it into Equation 1 

2(2y - 1) + y = 3       Solve for y.
4y - 2 + y = 3
<u>    +2          +2 </u>          Combine like terms and isolate y.
4y + y  =  5
        5y = 5               Isolate y by dividing both sides by 5
5y/5  =   5/5
  y   =   1  

With y solved, solve either system for x.

x = 2(1) - 1
x = 2-1 
x = 1

Solution is (1,1)


Shalnov [3]3 years ago
7 0
2(2y-1)+y=3
y=1
x=2 x1 - 1
x=1
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The lower trapezoid:

Use the formula \frac{1}{2}(base_{1} + base_{2}) (height) to compute the area of the trapezoid. Base 1 = 10, Base 2 = 3 and Height = 5.

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