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charle [14.2K]
3 years ago
13

Geometry What is the range of possible values for x? The diagram is not to scale.

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0
Where is the diagram? How do we answer without it?
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Pleaseee help me with this problem
Liula [17]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
PLEASE HELP! I need help on this
Alja [10]
99+2x=180
x=40.5
99>
40.5
6 0
3 years ago
(39PTS)Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled
kherson [118]
Car A traveled 55 miles per hour. Now, how I got this is with the distance= rate *time equation. You can send me a message if you need a more detailed explanation. Hope this helped. 
3 0
3 years ago
Help me with this pls
bazaltina [42]

Answer:

D. 60=(x+45)

Step-by-step explanation:

They are the same degree so they should equal eachother

3 0
3 years ago
Read 2 more answers
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