First you would have to isolate y.
3x - 3y = 18 -----> Subtract 3x from both sides
-3y = -3x + 18 --------> Now divide both sides by -3
y= x - 6
Now you replace the y with an f(x)
f(x) = x - 6
Answer:
Angle A is 29 degress Angle B is 61 Angle C is 90
Side AB is 5.8 Side BC is 2.8 and Side AC is 5.1
Step-by-step explanation:
Angle A is found using triangle interior theorem.
I found side AC by using law of sines
b/sin b= c/sin c
x/sin 61= 5.8/sin 90( which equal 1)
x=5.1
I found side BC by using pythagoren theorem.
a^2 + b^2=c^2
5.1^2+ b^2=5.8^2
26.01+b^2=36.64
b^2=7.63
b=approx 2.8.
The answer will be 35.8 , i calculated it
Answer:
w ≥ 6
Step-by-step explanation:
51 ≤ 15 +6w
51-15 ≤ 6w
36 ≤ 6w
6w ≥ 36
w ≥ 36/6
w ≥ 6