Geometry Help Please! Find the measure of angle 3? 72° 60° 54° 36°

Find an exponential function with a horizontal asymptote y equals=2 whose graph contains the points (0,3) and (1,6).

Andrew [12]

$\bf y=a(b)^x\qquad \qquad (\stackrel{x}{0}~,~\stackrel{y}{3})\implies 3=a(b)^0\implies 3=a
\\\\\\
therefore\qquad y=3(b)^x\\\\
-------------------------------\\\\
(\stackrel{x}{1}~,~\stackrel{y}{6})\implies 6=3(b)^1\implies \cfrac{6}{3}=b^1\implies 2=b
\\\\\\
therefore\qquad y=3(2)^x$

now, exponential functions have a horizontal asymptote at the x-axis, namely when y = 0, however, if you just move this one with a vertical translation of 2, then the horizontal asymptote will be at 2 instead. y = 3(2)ˣ + 2

6 0

2 years ago

Zachary final project for a college course took A semester to write and had 95,234 words Zachary wrote 35 ,295 words the first m

natulia [17]

It is these nuts go chu now do your own homework

4 0

2 years ago

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

sveticcg [70]

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
If x and y coordinates are positive, then the angle lies in the 1st quadrant
If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
If x and y coordinates are negative, then the angle lies in the 3rd quadrant
If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point $(\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})$

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = $\frac{-\sqrt{2} }{2}$

∴ cosФ = $\frac{-\sqrt{2} }{2}$

∵ y-coordinate = $\frac{\sqrt{2} }{2}$

∴ sinФ = $\frac{\sqrt{2} }{2}$

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = $\frac{-\sqrt{2} }{2}$ ÷ $\frac{\sqrt{2} }{2}$

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

4 0

3 years ago

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Identify the property or rule shown by each equation. 9 divided 1 =9 and 33 times 1 =33

kicyunya [14]

identity property=something times one

5 0

3 years ago

Please answer this question right now

Leokris [45]

Answer:

D.

Step-by-step explanation:

5 0

2 years ago

Geometry Help Please! Find the measure of angle 3? 72°60°54°36°