To find the work done on the particle, the following is the
solution:
Dw = F dx
W = integral over the path ( F(x) dx)
W = integral from 0 to 1 (e^(-x/5 + 5) dx)
W = -5e^(-x/5 + 5) from 0 to 1
W = 135 J
The work done is 135 J.
The first and the last segment ... 60 mi north and 60 mi south ... canceled
each other. The only segment left is the 100 mi west, so that's the overall
displacement ... 100 miles west. The times don't matter at all.
Answer:
19.2 m/s
Explanation:
The train is moving at 18 m/s and you are walking in the same direction (east) so the speeds are added
18 + 1.2 = 19.2
If you were walking backwards (west) your velocity with respect to the ground would be
18 - 1.2 = 16.8
An action-reaction pair shows the direct relationship two objects have <u>directly</u> on each other. Therefore, the correct answer is C. The Moons gravity pulls on you, and your gravity pulls on the Moon because it is moon gravity-person person gravity-moon.
Choice A would be made correct if it was you pull on a drawer and the drawer pushes on you OR the table pushes on the ground and the ground pushes on the table.
Choice B would be made correct if it was a computer sits on a table and the table pushes up on the computer.
Choice D would be made correct if it was an eraser sits on a shelf and the shelf pushes up on the eraser OR the wall pushes on the shelf and the shelf pushes against the wall.
Hope this helps!!
frequency of engine is given here
now we have angular speed as
similarly
now by the formula of angular acceleration we will have