22 + (30 - 4) divided by 2
30 - 4 = 26
26/2 = 13
22 + 13 = 35
35
18 + (22 - 4) divided by 6
22 - 4 = 18
18 divided by 6 = 3
18 + 3 = 21
21
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
If point A is between B and C, then CA+AB = CB by the segment addition postulate. This is the idea of taking two smaller segments to "glue" them together to form a larger segment. Or you can think in reverse: take some larger segment and split it somewhere in between the endpoints (not necessarily the halfway point), this will produce two smaller segments.
For example: you have a ruler that is 12 inches. Take a saw and cut the ruler at the "2 inch" marker. You'll end up with two smaller pieces of plastic: one of which is 2 inches, the other 10 inches. The two smaller pieces can be taped together to reform the original 12 inch ruler.
Answer:
3 feet
Step-by-step explanation:
half his height
Answer:
Ab^2 = CA^2 + BC^2
8^2 = 6^2 + a^2
64 = 36 + a^2
64-36 = a^2
28 = a^2
square root of 28 = square root of a^2
5 ,29 = a
5 = a
