I mostly just need the steps on how to do it.
1 answer:
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Perimeter of triangle ABC is 20 units.
Solution:
The image for reference is attached below.
Given AE = 2, BD = 5 and CF = 3
Two tangents drawn from an external point to a circle are equal in length.
AD = AE, BF = BD and CE = CF
Therefore, AD = 2, BF = 5 and CE = 3
Perimeter of the triangle = sum of the three sides
Perimeter of triangle ABC = AB + BC + CA
= AD + BD + BF + CF + CE + AE
= 2 + 5 + 5 + 3 + 3 + 2
= 20
Hence, perimeter of triangle ABC is 20 units.
Answer:
16
Step-by-step explanation:
a = age
- you will multiply by 8 now
- now move a's with a's and the numbers that don't have a variable with each other
- now subtract
- I hope it helps you!