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Pachacha [2.7K]
3 years ago
8

Find a line perpendicular to -5y=-35/2x+10 that goes through point(7,4)

Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

y=-2/7x+6

Step-by-step explanation:

first write this in y=mx+b format, y=7/2x−2

then write the perpendicular line, which is the opposite & negative of m

y=−2/7x-2

then remove b

y=−2/7x+b

plug in the numbers

(7,4) y= 4 x=7

4=-2/7*7+b

b is 6

so put the numbers back in

y=-2/7x+6

hope this helps and have a great day

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Free_Kalibri [48]

Answer:

28

Step-by-step explanation:

So in order to get this answer you want to use the combination formula which is \frac{n!}{(n-r)!r!}

Now you want to use the numbers given to you in the problem which is ₈C₂ and plug those into the equation

so your going to have something looking like this \frac{8!}{(8-2)!2!}  now if you have a calculator nearby and you plug in ₈C₂ your going to get 28 which is the answer.

hope this somewhat helps.

7 0
3 years ago
Geometry help. Inscribing circle help and constructing lines.
prohojiy [21]
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>

To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.

1. Draw the angle bisector of angle JKL. The straight line in the green one.

2. Draw the angle bisector of angle KLJ. The straight line in the blue one.

3. Draw point D at these two lines.

4. Draw a line through point D perpendicular to side JK. The straight line in the red one.

5. Mark point G at the red line and side JK.

6. Draw a circle with center at D (point of concurrency) and a radius of DG.


<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>

To circumscribe a circle in the attached triangle, we must follow the following steps:

1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.

2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.

3. The center of the circle is the intersection of these two lines

4. Draw a circle with center at D (point of concurrency).

<h3>3. Construct the two lines tangents to circle</h3>

A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.

3 0
3 years ago
What is the area of angle GHI
steposvetlana [31]
6.4

1/2 * 5.4 * 7.1 sin60


Mark brainliest please
3 0
3 years ago
DO, -2(x, y) ----- (3, 5).
Alenkinab [10]

Answer:

C (-6,10) - A)x^7-0.1/4

Step-by-step explanation:

Hope this helps

3 0
3 years ago
Read 2 more answers
Question 3
Elan Coil [88]

Answer:

Domain:  -3\leq x\leq 1

Range:  -4\leq y\leq 0

Step-by-step explanation:

If you find the coordinate of the graph you can get the domain and range

(-3,0), (-2,-4), (-1,-2), (0,0), (1, -4)

Now that we have that find the domain and range

Domain -  x coordinate

Range - y coordinate

Domain: (-3, -2, -1, 0, 1)

Range: (-4, -2, 0)

Since the domain ranges from -3 to 1 you can use the inequality -3\leq x\leq 1 to represent the domain and -4\leq y\leq 0 for the range

7 0
3 years ago
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