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2 years ago

Find a line perpendicular to -5y=-35/2x+10 that goes through point(7,4)

Mathematics

1 answer:

valina [46]2 years ago

5 0

Answer:

y=-2/7x+6

Step-by-step explanation:

first write this in y=mx+b format, y=7/2x−2

then write the perpendicular line, which is the opposite & negative of m

y=−2/7x-2

then remove b

y=−2/7x+b

plug in the numbers

(7,4) y= 4 x=7

4=-2/7*7+b

b is 6

so put the numbers back in

y=-2/7x+6

hope this helps and have a great day

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The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. • If t

son4ous [18]

Answer:

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

There is a 15.87% probability of failure of the cable.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The breaking strength of a cable is assumed to be lognormally distributed with a mean of 75 and standard deviation of 20. This means that $\mu = 75, \sigma = 20$ .

If the load of magnitude 50 is hung from the cable, determine the probability of failure of the cable?

This is the pvalue of Z when $X = 50$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 75}{20}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1056.

There is a 10.56% probability of failure of the cable.

If the load can take values 30, 50, and 70 with probabilities 0.2, 0.35, and 0.45 respectively, determine the probability of failure of the cable?

Now we have that

$X = 0.2(30) + 0.35(50) + 0.45(70) = 55$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 75}{20}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587.

There is a 15.87% probability of failure of the cable.

3 0

3 years ago

Answer and show work

sertanlavr [38]

Answer:

3x+2/4>-20

3x+2>-80

3x>-80-2

3x>-82

x>-82/3

Also simplified to, x>-27 1/3

8 0

2 years ago

Read 2 more answers

Whats the difference of 2 times d minus 3

Dmitriy789 [7]

Answer:

2(d - 3) is the equation. You cannot solve for d. You can only simplify it

7 0

2 years ago

Thirty elves would like to build a skating ring so they can all use it at the same time. Santa tells them, they need at least 40

Delicious77 [7]

Answer:

The Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

Step-by-step explanation:

Given:

Number of skaters = 30

Area for each skater = 40 sq ft

We need to find the dimension of rectangular ring the are going to build.

Now we know that they building the skating ring such that they all can use at same time.

Hence if the all use at same time then we will find the total area first.

Total area can be calculated by multiplying Number of skaters with area required for each skaters.

Framing the equation we get;

Total area = $30\times 40 = 1200 \ ft^2$

Hence The total area of the rectangular ring would be 1200 sq. ft.

Now we know that Total area is equal to product of length and width.

$length\times width =1200ft^2$

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30

Hence the Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

3 0

2 years ago

3 equivalent ratios for 5/7

riadik2000 [5.3K]

Answer:

10/14, 15/21, and 20,28

Step-by-step explanation:

You just need to multiply a number on the numerator and the denominator. Remember, whatever you do to the numerator you have to do on your denominator.

8 0

2 years ago