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3 years ago

Tan^2theta - Sin^2theta = tan^2theta. sin^2theta explain this step

Mathematics

1 answer:

denis23 [38]3 years ago

8 0

tan²(θ) - sin²(θ) = sin²(θ)/cos²(θ) - sin²(θ)

-- because tan(θ) = sin(θ)/cos(θ) by definition of tangent --

… = sin²(θ) (1/cos²(θ) - 1)

-- we pull out the common factor of sin²(θ) from both terms --

… = sin²(θ) (1/cos²(θ) - cos²(θ)/cos²(θ))

-- because x/x = 1 (so long as x ≠ 0) --

… = sin²(θ) ((1 - cos²(θ))/cos²(θ))

-- we simply combine the fractions, which we can do because of the common denominator of cos²(θ) --

… = sin²(θ) (sin²(θ)/cos²(θ))

-- due to the Pythagorean identity, sin²(θ) + cos²(θ) = 1 --

… = sin²(θ) tan²(θ)

-- again, by definition of tan(θ) --

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x=number of hours

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y-intercept= (0, 75)

Equation= y=25x+75

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Step-by-step explanation:

75 would be the y intercept(constant) because that's the initial charge for a call.

25 would be the coefficient for x because the hour you spend on the call varies.

The slope is how steep the line is, in this case it is 25.

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Step-by-step explanation:

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2 years ago

(08.07 HC)

andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

To factor a quadratic in the form $ax^2+bx+c$ , find two numbers that multiply to $ac$ and sum to $b$ :

$\implies ac=2 \cdot -10=-20$

$\implies b=-1$

Therefore, the two numbers are -5 and 4.

Rewrite $b$ as the sum of these two numbers:

$\implies f(x)=2x^2-5x+4x-10$

Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

$\implies (2x-5)=0 \implies x=\dfrac{5}{2}$

So the x-intercepts are:

$x=-2, \:\:x=\dfrac{5}{2}$

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the leading coefficient of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the x-value of the vertex. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is symmetrical.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0

1 year ago

Can someone please help me with this question!!!!!

Firlakuza [10]

I think it's C biceptor

5 0

3 years ago

Please me help me help me

Oksana_A [137]

Answer:

Its 60 degrees

Step-by-step explanation:

Opposite angles are equal so then CGE is the same as FGD and since angle CGB is a right angle we can subract the 30 from 90 and get a 60

6 0

2 years ago

Tan^2theta - Sin^2theta = tan^2theta. sin^2theta explain this step​

Tan^2theta - Sin^2theta = tan^2theta. sin^2theta explain this step