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3 years ago

Write the sentence as an equation.

Mathematics

2 answers:

kow [346]3 years ago

6 0

Answer:

257k-392=153

the product of 257 and k means you are multiplying 257 and k. 392 is subtracted from that product so you put that subtraction sign after the multiplication problem. The same as means the answer is equal to 153.

bulgar [2K]3 years ago

5 0

Answer:

257k-392=153

Step-by-step explanation:

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Which of the following values represent a meaningful difference between two populations? Select all that apply.

Lina20 [59]

Answer: I got you if its not to late the answer is 2,3

Step-by-step explanation

anything above 2 is meaningful so first you would subtract 21.9 28.1 to get 3.7 its above 2 so that's one do the same for the rest anything above 2 is your answer or right at two really hope this helps

6 0

3 years ago

PLEASE HELP

Rudik [331]

$y=75\ \ \ \ x=5\\\\
y=?\ \ \ \ \ x=3\\\\
proportion:\\
\frac{75}{y}=\frac{5}{3}\ \ \ | cross\ multiplication\\\\
75*3=5y\\\\
225=5y\ \ \ | divide\ by\ 5\\\\
y=45
$

5 0

4 years ago

use the formula a=p(1+r/n)nt to find the compound interest account . zakk deposited $5600.0in an account which compounded 1.9%qu

Komok [63]

Answer:

$A=\$6,768.75$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$5,600\\ r=0.019\\n=4$

substitute in the formula above

$A=\$5,600(1+\frac{0.019}{4})^{4*10}$

$A=\$5,600(1.00475)^{40}=\$6,768.75$

5 0

3 years ago

The table below shows the scores on a science test.

viva [34]

Count the same scores and make a list:

There are two 75's

Three 80's

Two 85's

Two 90's and one 100

Now find the chart that has those same values.

The answer would be B.

3 0

3 years ago

UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of

11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

Let $\mu$ = population average time someone spends in the gym

SO, Null Hypothesis, $H_0$ : $\mu$ = 56 minutes {means that the average time someone spends in the gym is 56 minutes}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 56 minutes {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average time someone takes in the gym = 50 min

$\sigma$ = population standard deviation = 8 minutes

n = sample of gym goers = 32

So, test statistics = $\frac{50-56}{\frac{8}{\sqrt{32} } }$

= -4.243

Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0

3 years ago