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3 years ago

PLEASE HELP ME ( I ADDED A PHOTO)

Mathematics

2 answers:

Reil [10]3 years ago

7 0

Answer:

um 32-28 so 12.5 i think for the first one the second one is 25%

i am so sorry if i get it wrong

Step-by-step explanation:

Nostrana [21]3 years ago

4 0

Answer:

Which one do you need help with

Step-by-step explanation:

Im not just taking points I will still help you in the comments.

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Help please. Solve the system of equations using substitution. Show your work in the workspace provided below.

LenKa [72]

Answer:

x=0 y=-11 (0,-11)

Step-by-step explanation:

1. take what y equals (3x-11) and plug it in for y in the second equation

Should look like this: O= 6x-2(3x-11)-22

2. Then distribute O=6x-6x+22-22

3. Then combine like terms O= 0 the 22's cancel out as well as the x's

x= 0

4. plug 0 in for x in the first equation y=3(0)-11

5. y= -11

6. x=0 y=-11 (0,-11)

6 0

3 years ago

What is the perimeter of a rectangle that has a length of 40 Ft and a width of 17 ft?

statuscvo [17]

Answer:

i think 114ft

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

Which expression is equivalent to 2 (14x-37+28x+12.2-5y-17.5)?

ziro4ka [17]

Answer:

A. 84x - 16y - 10.6

Explanation:

$\sf \rightarrow 2(14x-3y+28x+12.2-5y-17.5)$

$\sf \rightarrow 2 (42x-8y-5.3)$

apply distributive method: a(b + c) = ab + ac

$\sf \rightarrow 2 (42x) -2(8y)-2(5.3)$

$\sf \rightarrow 84x -16y-10.6$

7 0

2 years ago

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago

9. What type of transformation is shown?

gizmo_the_mogwai [7]

A reflection I think is true

7 0

2 years ago