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Ghella [55]
4 years ago
7

Which of the following is mainly considered for use in electric vehicles?

Chemistry
1 answer:
jolli1 [7]4 years ago
4 0
Answer is A: hydrogen fuel
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Part b (r)–3-chloro-2-methylhexane will undergo a nucleophilic substitution reaction in the presence of sodium ethoxide and etha
arsen [322]

Answer:

See answer below

Explanation:

To understand this, we need to make the reaction involved with the given configuration. Configuration R means that the substituents of the molecule, the priority order goes clockwise (From heaviest to lightest) so, if an Sn2 is ocurring in the reaction this means that the nucleophile, which in this case, is the sodium ethoxide will attack the molecule in the opposite side of the leaving group (which is the chlorine).

Also when this occurs, as Sn2 is a bimolecular reaction and is held in one step, it occurs an inversion in the configuration of the product. So, it's the innitial reactant was R, then the final product will be S.

The mechanism and product can be watched in the attached picture

Hope this helps.

8 0
3 years ago
The smell of dirty gym socks is caused by the compound caproic acid(contains H, C, O). Combustion of 0.844 g of caproic acid pro
adoni [48]

<u>Answer:</u> The molecular formula for the given organic compound is C_2H_{32}O_4

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.784g

Mass of H_2O=1.92g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.784 g of carbon dioxide, \frac{12}{44}\times 0.784=0.214g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.92 g of water, \frac{2}{18}\times 1.92=0.213g of hydrogen will be contained.

Mass of oxygen in the compound = (0.844) - (0.214 + 0.213) = 0.417 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.214g}{12g/mole}=0.0134moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.213g}{1g/mole}=0.213moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.417g}{16g/mole}=0.0261moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0134 moles.

For Carbon = \frac{0.0134}{0.0134}=1

For Hydrogen = \frac{0.213}{0.0134}=15.89\approx 16

For Oxygen = \frac{0.0261}{0.0134}=1.95\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 16 : 2

The empirical formula for the given compound is CH_{16}O_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 116.2 g/mol

Mass of empirical formula = 60 g/mol

Putting values in above equation, we get:

n=\frac{116.2g/mol}{60g/mol}=1.94\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 2)}H_{(16\times 2)}O_{(2\times 2)}=C_2H_{32}O_4

Hence, the molecular formula for the given organic compound is C_2H_{32}O_4

5 0
3 years ago
What are The advantages of using scientific procedures in doing science experiments?
Studentka2010 [4]

Answer:

Doing experiments by scientific procedures is advantageous and helpful.

Explanation:

The scientific procedure should be followed while performing a experiment as it has many advantages like:

  • Working in safe environment: Performing a experiment by scientific procedure ensures the safety of the experimenter.
  • It reduces the chances of mistakes: The proper availability of the scientific equipment helps in reduction of the chances of the mistakes.
  • A sequence of steps is followed: A proper sequence of steps is followed to perform a experiment step by step. Performing experiment without scientific procedure may cause the experimenter to forgot a step.
  • More Accuracy: The readings of the experiment is more accurate by doing experiment by scientifically.
  • Chemical changes can be observed: The physical and chemical changes can be observed and can be measured by the lab equipment to perform more accurately.
  • less chance of risks: Performing in the safe scientific environment and using proper safety equipment reduces the chances of risks to the experimenter.

5 0
3 years ago
What is an example of a microorganism acting in a harmful way? A) Bacteria aiding digestion. B) Bacteria causing strep throat. C
vaieri [72.5K]
Not very often, but sometimes, the language gives away the question. This is one such instance.

Look at A. Is digestion a bad thing? It shouldn't be. Otherwise you run marathons with gobs of food not being broken down and providing energy. 
Not A.

Not C. Do you like yogurt? If you don't do you know someone who does? Is yogurt for you/them a bad thing. Bacteria here are good. Again, not C.

Not D. Waste is bad. It's a problem. Getting rid of it is good. Again not D.

There's only one left.
B <<<< answer. Who would like to get strep throat. It's a fate for your worst enemy.

B <<<< answer.
4 0
3 years ago
Read 2 more answers
Which disney character am I thinking of: he has a green outfit and a green hat
LuckyWell [14K]

i don't know peter pan??

3 0
3 years ago
Read 2 more answers
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