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Grace [21]
3 years ago
9

The total number of protons and neutrons in the nucleus of an atom is called the___________

Chemistry
1 answer:
Helen [10]3 years ago
6 0
This answer is nucleons
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Most reactions speed up when
miss Akunina [59]
For a reaction to occur, there should be mobility of ions in reactant side.
If the reactant is larger, its mobility will be lesser than that of smaller ones.
So reactants smaller in size have higher mobility which makes reaction faster.

Hence D is the correct option.

Hope this helps, have a great day/night ahead!
7 0
3 years ago
Read 2 more answers
Express the chemical reaction between hydrogen and oxygen elements for the formation of water in word equation and chemical equa
White raven [17]

Answer:

Two moles of hydrogen gas combine with one mole of oxygen gas to produce two moles of water.

2H_{2} O + O_{2}  -> 2H_{2}O

Explanation:

This is the required amount of each element to synthesize water. The equation has been balanced using coefficients.

7 0
3 years ago
9. In a titration experiment 34.7 of a 0.145M solution of barium hydroxide \ Ba(OH) 2 \ is added to 20mL of hydrochloric acid (H
Ksenya-84 [330]

Answer:

Titration reveals that 12 mL of 1.5 M hydrochloric acid are required to neutralize 25 mL calcium hydroxide solution . What is the molarity of the Ca(OH) 2 solution

Explanation:

8 0
1 year ago
What is the process of shedding feathers and growing new ones back
laiz [17]
Molting

~~~hope this helps~~~
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3 0
3 years ago
Given that it requires 27.9 ml of 0.270 m na2s2o3(aq) to titrate a 15.0-ml sample of i3–(aq), calculate the molarity of i3–(aq)
Digiron [165]

The molar concentration of the KI_3 solution is 0.251 mol/L.

<em>Step 1</em>. Write the <em>balanced chemical equation</em>

I_3^(-) + 2S_2O_3^(2-) → 3I^(-) + S_4O_6^(2-)

<em>Step 2</em>. Calculate the <em>moles of S_2O_3^(2-)</em>

Moles of S_2O_3^(2-)

= 27.9 mL S_2O_3^(2-) ×[0.270 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)]

= 7.533 mmol S_2O_3^(2-)

<em>Step 3</em>. Calculate the <em>moles of I_3^(-) </em>

Moles of I_3^(-) = 7.533 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 3.766 mmol I_3^(-)

<em>Step 4</em>. Calculate the <em>molar concentration of the I_3^(-) </em>

<em>c</em> = "moles"/"litres" = 3.766 mmol/15.0 mL = 0.251 mol/L

6 0
3 years ago
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