From A to B...
distance formula : sqrt ((x2 - x1)^2 + (y2 - y1)^2
(-3,1)....x1 = -3 and y1 = 1
(1,3)....x2 = 1 and y2 = 3
sub
d = sqrt ((1 - (-3)^2 + (3 - 1)^2
d = sqrt ((1 + 3)^2 + 2^2
d = sqrt (4^2 + 2^2)
d = sqrt (16 + 4)
d = sqrt 20
d = 4.47 miles...so from A to B, it was 4.47 miles
from B to C
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2
(1,3)....x1 = 1 and y1 = 3
(5,-1)...x2 = 5 and y2 = 1
sub
d = sqrt ((5 - 1)^2 + (-1 - 3)^2
d = sqrt ((4^2 + (-4^2)
d = sqrt (16 + 16)
d = sqrt 32
d = 5.66......but keep in mind, he only drove half-way...so 5.66/2 = 2.83 miles
for a total of : 4.47 + 2.83 = 7.3 miles <===
<span>8(R + 6) - 2R,
8R + 48 - 2R,
The result is 6R + 48</span>
Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
Answer:
7 3/20
Step-by-step explanation:
I took the quiz.
